# Line slope calculator x-3y=-5

**Straight line given by points A[1; 2] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.3333x+1.6667

**Canonical form of the line equation:**x-3y+5 = 0

**Parametric form of the line equation:**

x = 3t+1

y = t+2 ; t ∈ R

**Slope:**m = 0.3333

**Slope angle of line: φ =**18°26'6″ = 0.3218 rad

**X intercept:**x

_{0}= -5

**Y intercept:**y

_{0}= q = 1.6667

**Distance line from the origin:**d

_{0}= 1.5811

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(3; 1)

**Normal vector: n =**(1; -3)

**Midpoint of the segment AB: M =**[2.5; 2.5]

**Perpendicular Bisector equation:**3x+y-10 = 0

**Vector OA = (1; 2) ; |OA| = 2.2361**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**