Check whether number is palindrome or not - Leet Code Solution

August 28, 2019

Problem Statement

Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward.

Example 1:

Input: 121
Output: true

Example 2:

Input: -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.

Example 3:

Input: 10
Output: false

Algorithms

There can be many solutions to this:

Convert number to character array, and keep on matching characters.
Reverse whole number and compare
Get the length of number, and iterate over number digit by digit

Solution - Reverse number and compare

public class Q9_Palindrome {
	private int reverseInt(int x) {
		int s = 0;
		while (x > 0) {
			s = s*10 + x%10;
			x = x/10;
		}
		return s;
	}
	
    public boolean isPalindrome(int x) {
    	if (x < 0) return false;
    	return x == this.reverseInt(x);
    }
}

Solution - Iterate over number digit by digit

public class Q9_Palindrome {
    /**
     * Example: 1234
     * place=0, result=4
     * place=1, result=3
     */
    private int getDigit(int x, int place) {
    	x = x / (int)Math.pow(10, place);
    	return x % 10;
    }
    
    public boolean isPalindrome(int x) {
    	if (x < 0) return false;
    	int l = 0;
    	int temp = x;
    	while (temp > 0) {
    		l++;
    		temp /= 10;
    	}
    	
    	for (int i=0; i<l; i++) {
    		if (this.getDigit(x, i) != this.getDigit(x, l-1-i)) {
    			return false;
    		}
    	}
    	return true;
    }
}